(1/3)^4x+5=9^x-2

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Solution for (1/3)^4x+5=9^x-2 equation: 



(1/3)^4x+5=9^x-2

We move all terms to the left:

(1/3)^4x+5-(9^x-2)=0



Domain of the equation: 3)^4x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/3)^4x-(9^x-2)+5=0

We get rid of parentheses

(+1/3)^4x-9^x+2+5=0

We multiply all the terms by the denominator


(+1-9^x*3)^4x+2*3)^4x+5*3)^4x=0

Wy multiply elements

18x^2+(+1-9^x*3)^4x=0

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